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13. Calculate the area of the parallelogram whose adjacent sides are a=[1,1,−2] and b=[3,3,−1].

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Answer:

the area of the parallelogram with adjacent sides a=[1, 1, -2] and b=[3, 3, -1] is approximately 10.2956 square units.

Explanation:

To calculate the area of a parallelogram, we can use the formula: Area = magnitude of the cross product of the adjacent sides.

Given the adjacent sides:

a = [1, 1, -2]

b = [3, 3, -1]

We can calculate the cross product of a and b to find the area.

1. Calculate the cross product of a and b:

Cross product = [a2 * b3 - a3 * b2, a3 * b1 - a1 * b3, a1 * b2 - a2 * b1]

= [1 * (-1) - (-2) * 3, (-2) * 3 - 1 * 3, 1 * 3 - 1 * 3]

= [-1 + 6, -6 - 3, 3 - 3]

= [5, -9, 0]

2. Find the magnitude of the cross product:

Magnitude = sqrt(5^2 + (-9)^2 + 0^2)

= sqrt(25 + 81 + 0)

= sqrt(106)

≈ 10.2956

Therefore, the area of the parallelogram with adjacent sides a=[1, 1, -2] and b=[3, 3, -1] is approximately 10.2956 square units.

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