Question

How many liters of radon gas would be in 3.43 moles at room temperature and pressure (293 K and 100 kPa)?

O A. 6.99 L
B. 6.53 L
O C. 100 L
D. 82.32 L

Answer 1

Answer: D. 82.32 L

Step-by-step explanation:

we can use the ideal gas law:

PV = nRT

Where:

P = pressure (in kPa)

V = volume (in liters)

n = number of moles

R = ideal gas constant (in LkPa/molK)

T = temperature (in Kelvin)

Given:

P = 100 kPa

n = 3.43 moles

R = 8.314 LkPa/molK (this is the universal gas constant)

T = 293 K

Rearranging the ideal gas law to solve for V:

V = nRT/P

Plugging in the given values:

V = (3.43 moles * 8.314 LkPa/molK * 293 K) / 100 kPa

V = (3.43 * 8.314 * 293) / 100

V = 83.24 / 100

V = 82.32 L

So, the answer is:

D. 82.32 L