Question

5. A box contains 10 marbles, 7 of which are yellow and three are green. If two balls are drawn from the bag one after the other without replacement. Find the probability of getting: a. a green, then a yellow b. A green and a yellow c. Same color ​

Answer 1

a. To find the probability of getting a green, then a yellow, we multiply the probabilities of each event. The probability of getting a green on the first draw is 3/10. After removing one green marble, there are 9 marbles left, 6 of which are yellow. So the probability of getting a yellow on the second draw is 6/9. Multiply these probabilities together to get the overall probability.

b. To find the probability of getting a green and a yellow, we again multiply the probabilities of each event. The probability of getting a green on the first draw is 3/10. After removing one green marble, there are 9 marbles left, and the probability of getting a yellow on the second draw is 7/9. Multiply these probabilities together to get the overall probability.

c. To find the probability of getting the same color, we need to consider two scenarios: both green or both yellow. The probability of getting two greens is (3/10) * (2/9), and the probability of getting two yellows is (7/10) * (6/9). Add these probabilities together to get the overall probability.