Question

Need helpz can’t figure it out

Answer 1

Answer:
`\pm√(-48)=\pm4i√(3)`

Explanation:

The square root of negative one is the imaginary unit, i. In the same way, i² = - 1.

`\pm√(-48)=\pm4i√(3)`

48 is divisible by 16 and 3. Since 16 is a perfect square, take 4 out of the radicand. The 3 remains because the sqrt of 3 is odd and not a perfect square. The i typically gets pit at the front because it can be hard to tell that the i is outside of the square root symbol.