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I require help with this math issue. please awnser p=2l+2w

I require help with this math issue. please awnser p=2l+2w-example-1

2 Answers

0 votes

Answer:

the field is 53 feet long by 47 feet wide

Explanation:

w = width

l = length = w + 6

P = 2w + 2l substitute l = w + 6 into the equation

P = 2w + 2(w + 6) = 200

solve for w:

200 = 2w + 2w + 12 = 4w + 12

4w = 200 - 12 = 188

w = 188/4 = 47

l = 47 + 6 = 53

5 votes

Answer:

Width (W) = 49 feet

Length (L) = 55 feet

Explanation:

Let's use the given formula to solve this problem:

P - 2L + 2W = 0

where P is the perimeter of the rectangular field, L is the length, and W is the width.

We are given that the perimeter of the field is 208 feet, so we can substitute P = 208:

208 - 2L + 2W = 0

We are also given that the length of the field is 6 feet more than the width:

L = W + 6

We can substitute this expression for L in the equation above:

208 - 2(W + 6) + 2W = 0

Simplifying and solving for W:

208 - 2W - 12 + 2W = 0

196 = 4W

W = 49

Therefore, the width of the field is 49 feet. We can use the expression for L in terms of W to find the length:

L = W + 6 = 49 + 6 = 55

Therefore, the length of the field is 55 feet.

answered
User Lbolla
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