Question

A stone is dropped from the top of a cliff. It is seen to hit the ground below after 3.02 s . How tall is the cliff

Answer 1

44.7m

Step-by-step explanation:

Let's use the equation for motion s = ut + ½at², where s is distance/displacement, u is initial velocity, t is time, and a is acceleration.

The stone is dropped, not thrown, so its initial velocity is zero, u=0m/s. Were told it takes 3.02 to hit ground, so t=3.02s. The acceleration here is acceleration due to gravity, so a=g=9.81m/s/s.

Let's sub these values in:

s = ut + ½at²

s = (0)(3.02) + ½(9.81)(3.02)² = 44.735562