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The perimeter of a rectangle is 52 feet. Find its dimensions assuming that its length is feet less than twice its width.

asked
User Jancy
by
7.9k points

1 Answer

4 votes

Answer:

Width = 9 feet

Length = 17 feet

Explanation:

Let width = w

the length is feet less than twice its width

length = 2w - 1

The perimeter of a rectangle is 2(L+W)

52 = 2(2w - 1 + w)

52 = 2(3w - 1)

52 = 6w - 2

52 +2 = 6w

54 = 6w

w = 9

length = 2w - 1

l = 2(9) - 1

l = 18 - 1

l = 17

answered
User Jonathan Viccary
by
8.0k points

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