Answer:
Explanation:
Let's break down the information given to find the ages of the three oldest children.
1. There are 6 children in total, and they were each born one year apart for 6 consecutive years. This means that the ages of the children are consecutive integers.
2. The ages of the three oldest children add up to 57.
Let's assign variables to represent the ages of the children. We'll use x, x+1, x+2, x+3, x+4, and x+5 to represent the ages of the six children from youngest to oldest.
According to the second piece of information, we have the equation:
(x+3) + (x+4) + (x+5) = 57
Simplifying the equation, we get:
3x + 12 = 57
Subtracting 12 from both sides, we have:
3x = 45
Dividing both sides by 3, we find:
x = 15
Therefore, the ages of the three oldest children are 18, 19, and 20, and the ages of the other three children are 15, 16, and 17.
In summary, the three oldest children in the neighborhood are 18, 19, and 20 years old.