Question

A straight line passes through points (-2,1) and(6,3) find the equation of the line in the form y=mx+c where m and c are constants.

Answer 1

`y = (1)/(4 ) + (3)/(2)`

I hope it helps if not please be sure to tell me

Answer 2

m = (3 - 1)/(6 - (-2)) = 2/8 = 1/4

3 = (1/4)(6) + b

3 = 3/2 + b

b = 3/2

y = (1/4)x + (3/2)