Question

"Identify the error in the program given below.

my_dict = {'A' : 1, 'B' : 2, 'C' : 3, 'D' : 4, 'E' : 5} _popped = my_dict.pop('B', 6) print(f'Value popped: {_popped}') my_dict['F'] = 0 _popped = my_dict.pop('F', 0) _popped = my_dict.pop('B') print(f'Value popped: {_popped}')"

Answer 1

The error in the given program is that the key 'F' is being added to the dictionary before it was popped, causing a KeyError. The code can be fixed by rearranging the lines or removing the unnecessary pop statement.

Step-by-step explanation:

The error in the given program is that the key 'F' is being added to the dictionary my_dict using the statement my_dict['F'] = 0. However, before this statement, there is a line of code that attempts to pop the value of key 'F', which will throw a KeyError because the key 'F' does not exist in the dictionary yet.

To fix this error, you can either remove the line _popped = my_dict.pop('F', 0), or you can rearrange the code by adding the key-value pair before attempting to pop the value.

Here is the corrected version of the code:

my_dict = {'A': 1, 'B': 2, 'C': 3, 'D': 4, 'E': 5}
my_dict['F'] = 0
_popped = my_dict.pop('B', 6)
print(f'Value popped: {_popped}')
_popped = my_dict.pop('F', 0)
_popped = my_dict.pop('B')
print(f'Value popped: {_popped}')