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A flashlight, which uses two 5 V batteries in series, is turned on for 4 minutes. If the current in the flashlight is 312 mA, what is the energy dissipated in Joules?

A flashlight, which uses two 5 V batteries in series, is turned on for 4 minutes. If the current in the flashlight is 312 mA, what is the energy dissipated in Joules?
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A flashlight, which uses two 5 V batteries in series, is turned on for 4 minutes. If the current in the flashlight is 312 mA, what is the energy dissipated in Joules?

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User Coconup
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Answer: The equation for energy dissipated is 312

Step-by-step explanation:

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User Oren Melzer
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