Question

How much energy (KJ ) is required to convert a 15.5 g ice cube at −5.006C to liquid water at 90.0°C ? Heat of fusion of ice is 6.0 kJ/mol Specific heat capacity for ice and liquid water is 2.09 J/g−°C and 4.18 J/g−°C, respectively. 11.2 60.0 34.6 49.1 18.7

Answer 1

The total energy required to transform a 15.5 g ice cube at -5.0°C to liquid water at 90.0°C is approximately 11.2 kJ. This is obtained by adding the energy required to heat the ice to 0°C, the energy needed to change the state of the ice to water, and the energy needed to heat the water to 90.0°C.

Step-by-step explanation:

To calculate the total energy required to convert a 15.5 g ice cube at -5.0°C to liquid water at 90.0°C, several steps must be followed: