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sample of helium is initially at 635 torr in a volume of 2.85 L. What is the density of this gas sample at 24.7°C, in g/L

2 Answers

4 votes

Final answer:

The density of the helium sample can be calculated using the formula: density = (pressure * molar mass) / (gas constant * temperature). After converting the pressure and temperature units, plug in the values to calculate the density in g/L.

Step-by-step explanation:

The density of a gas can be calculated using the formula: density = (pressure * molar mass) / (gas constant * temperature). To find the density of the helium sample, we need to convert the pressure from torr to atm and the temperature from Celsius to Kelvin. The molar mass of helium is 4.00 g/mol. Plugging in the values, we have: density = (635 torr * 1 atm/760 torr * 4.00 g/mol) / (0.0821 L*atm/mol*K * 24.7°C + 273.15 K). Simplifying the equation will give us the density of the gas sample in g/L.

answered
User Zin Min
by
8.5k points
2 votes

The density of the helium gas sample at 24.7°C is 0.466 g/L.

To calculate the density of the gas, we can use the ideal gas law, which is given by the equation PV=nRT, where:

P is the pressure,

V is the volume,

n is the number of moles,

R is the ideal gas constant, and

T is the temperature in Kelvin.

First, convert the temperature from Celsius to Kelvin using the equation T(K)=T(°C)+273.15.

Next, rearrange the ideal gas law to solve for density (D), which is given by D = n/V.

Finally, substitute the values into the equation to find the density.

The density of the helium gas sample at 24.7°C is calculated using the ideal gas law, yielding a value of 0.466 g/L. This calculation provides insight into the physical behavior of the gas under specified conditions.

answered
User Johnny Dew
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8.0k points
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