Question

A battery with an emf of 12 V and an internal resistance of 1 Ω is used to charge a battery with an emf of 10 V and an internal resistance of 1 Ω. The current in the circuit is:

Answer 1

The current in the circuit is 1 ampere.

Step-by-step explanation:

To calculate the current in the circuit, you can use Ohm's law along with the concept of total resistance in a circuit with multiple components.

The total voltage across the circuit will be the difference in electromotive forces (EMFs) since they are connected in series:

Total voltage (V_total) = EMF1 - EMF2 = 12 V - 10 V = 2 V

The total resistance (R_total) is the sum of the internal resistances of both batteries:

R_total = R1 + R2 = 1 Ω + 1 Ω = 2 Ω

Now you can use Ohm's law to calculate the current (I) in the circuit:

I = V / R

Where:

I is the current flowing through the circuit.

V is the total voltage across the circuit.

R is the total resistance of the circuit.

Plugging in the values:

I = 2 V / 2 Ω = 1 A

So, the current in the circuit is 1 ampere.