asked 182k views
4 votes
URGENT PLEASE

A sample of argon gas has a volume of 68 mL at a pressure of 1.35atm and a temperature of 130 degrees Celsius. What is the final volume of the gas, in mL, when the pressure and temperature of the gas sample are changed to .75 atm and 85 degrees C.

asked
User Ezra
by
8.4k points

1 Answer

7 votes

Answer:

The volume that this gas occupies is 34.6L

Step-by-step explanation:

The volume that this gas occupies is 34.6L

Step-by-step explanation:

Let's start off with identifying our known and unknown variables.

The first volume we have is 12.0 L, the first pressure is 28.0 atm, and the second pressure is 9.70 atm. Our only unknown is the second volume.

We can obtain the answer using Boyle's Law which shows that there is an inverse relationship between pressure and volume as long as the temperature and number of moles remain constant.

The equation we use is P1V1=P2V2

where the numbers 1 and 2 represent the first and second conditions. All we have to do is rearrange the equation to solve for the volume.

We do this by dividing both sides by P2 in order to get V2 by itself like so:

P1V1 ÷P2 = V2

Now all we do is plug and chug!

(28.0 atm

)) (12.0 L) ÷ (9.70 atm)) = 34.6 L

answered
User Muhammad Hamada
by
8.2k points
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