Question

Midpoint of (3,5) and (-2,13)

Answer 1

x1 =3 ,x2 =5

y1=-2, y2=13

thus,

(x,y)=[ (x1+x2)/2 , y1+y2/2]

=(3+5/2 ,-2+13/2)

=8/2, 11/2)

=(4,11)