Answer:
1. The common difference in the sequence is 3. (Each term is 3 greater than the previous term.)
2. The 4th term in the sequence is 23.
3. A formula to describe this arithmetic sequence is:
\(f(x) = 14 + 3(x-1)\)
This formula represents an arithmetic sequence with an initial term of 14 and a common difference of 3.
4. To find the 100th term in the sequence, you can use the formula for an arithmetic sequence:
\(a_n = a_1 + (n-1)d\)
Where:
- \(a_n\) is the nth term,
- \(a_1\) is the first term,
- n is the term number,
- d is the common difference.
In this case, \(a_1 = 14\), the common difference \(d = 3\), and we want to find the 100th term (\(n = 100\)):
\(a_{100} = 14 + (100-1) \cdot 3\)
\(a_{100} = 14 + 99 \cdot 3\)
\(a_{100} = 14 + 297\)
\(a_{100} = 311\)
So, the value of the 100th term in the sequence is 311.
Explanation: