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3 votes
Factor the following polynomial complete 7q^(4)+14q^(2)-112q^(2)-224

asked
User AxelPAL
by
8.9k points

1 Answer

2 votes

Sure, let's factorize the given polynomial step by step.

Step 1: Combine like terms
Our polynomial is 7q^4 + 14q^2 - 112q^2 - 224. We have two terms involving q^2 that can be combined. Combining them yields

7q^4 - 98q^2 - 224.

Step 2: Common factor
Look for common factors in each term. The terms 7q^4, -98q^2, and -224 all share a common factor of 7. Factoring this out gives

7(q^4 - 14q^2 - 32).

Step 3: Factor Quadratic Expression
Now the polynomial is in the form of a quadratic expression: 7(q^2)^2 - 14q^2 - 32. To factorize it, find the two numbers that multiply together to give -32 (c term) and add together to give -14 (b term).

Those numbers are -16 and 2. Replacing -14q^2 with -16q^2 + 2q^2 gives

7[(q^2 - 16)q^2 + 2].

Step 4: Factor AQ^4 + BQ^2

This can be written as the product of two factors if it is in the form (AQ^2 + B)(Q^2 + C). Here, recognize that q^4 is the square of q^2, then we can rewrite the equation again in the form (A'Q'^2 + B')(Q'^2 + C) treating q^2 like a variable Q'. So, that gives us

7[(q^2 - 4)(q^2 + 4) + 2].

Step 5: Rearrange
Finally, rearranging the terms, we get

7*(q - 4)*(q + 4)*(q^2 + 2) which is our factored polynomial.

answered
User Joel Eckroth
by
8.0k points
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