The line that we are looking for can be expressed through its slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.
First, we know that the slope 'm' of the equation is given as 3/8, or 0.375.
Second, we know that this line passes through the point (15.2, -7). We can substitute these values into the equation y = mx + b, which gives us -7 = 0.375*15.2 + b.
To find the y-intercept 'b', we simply isolate it in the equation, which results in b = -7 - 0.375*15.2. After doing the calculation, we find that b equals -12.7.
Therefore, the equation of the line that has a slope of 3/8 and passes through the point (15.2, -7) is y = 0.375x - 12.7.