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Given: y^(2)-12x+4y-32=0 Write the equation in standard form:

1 Answer

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To answer the question, we need to re-arrange the given equation to be in the standard form. The given equation is y^2 - 12x + 4y - 32 = 0, which is a quadratic equation in two variables x and y.

Let's begin by rearranging the given equation such that the terms of y and x are separate:

y^2 + 4y + x - 12 = 32.

To continue, we need to complete the squares for the terms of x and y:

(y + 2)^2 - 4 + x - 12 = 32.

Simplified, this becomes:

(y + 2)^2 + x - 16 = 0.

This can be re-written as:

x = - (y + 2)^2 + 16.

Finally, let's rewrite this formula in standard form:

(x - 16) = - (y - (-2))^2.

This transformation concludes the process of converting the given equation to standard form. The standard form of the given equation is (x - 16) = - (y - (-2))^2.

answered
User Mehrdad Faraji
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