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Movement of the progress bar may be uneve Which one of the following 3x+1<5x+7 and

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User Shedrack
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1 Answer

6 votes

Hello!

Answer:


\Large \boxed{\sf x > -3}

Explanation:

We want to solve this inequation:


\sf 3x+1 < 5x+7

Subtract 3x from both sides:


\sf 3x+1-3x < 5x+7-3x

Simplify both sides:


\sf 1 < 2x+7

Subtract 7 from both sides:


\sf 1-7 < 2x+7-7

Simplify both sides:


\sf -6 < 2x

Divide both sides by 2:


\sf (-6)/(2) < (2x)/(2)

Simplify both sides:


\sf -3 < x

Turn the signe:


\boxed{\sf x > -3}

Conclusion:

The solution of the inequation 3x+1<5x+7 is all values greater than -3.

answered
User Arlene Batada
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