Question

Angle θ is in standard position and (−5,−6) is a point on the terminal side of θ. What is the exact value of cscθ in simplest form with a rational denominator?

Answer 1

Explanation:

First find the hypotenuse magnitude:

sqrt ( (-5)^2 + (-6)^2) = sqrt (61)

sin Φ is then ( OPPOSITE LEG / HYPOTENUSE ) :

-6 / sqrt (61)

csc = 1/ sin = - sqrt(61) / 6