Question

A recent survey by the American Automobile Association showed that a

family of two adults and two children on vacation in the United States will
pay an average of $247 per day for food and lodging with a standard
deviation of $60 per day. If the data are normally distributed, find the
percentage of these families who spent:
f. Between $200 and $300 per day.
Your answer
★ 1 point

Answer 1

To find the percentage of families who spent between $200 and $300 per day, you can use the standard normal distribution and z-scores. The formula for calculating the z-score is:

z = (x - μ) / σ

Where:
- x is the value you're interested in (in this case, $200 and $300)
- μ is the mean ($247)
- σ is the standard deviation ($60)

Calculate the z-scores for both $200 and $300, then use a standard normal distribution table or calculator to find the corresponding cumulative probabilities for each z-score. Finally, subtract the lower cumulative probability from the higher one to find the percentage of families who spent between $200 and $300 per day.

Let me know if you need further assistance with the calculations!