Question

Find the 15th term of a sequence whose first term is 6 and whose common difference is 7​

Answer 1

`n^(th)\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^(th)\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=6\\ d=7\\ n=15 \end{cases} \\\\\\ a_(15)=6+(15-1)7\implies a_(15)=6+(14)7\implies a_(15)=6+98\implies a_(15)=104`