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An object is placed at the position x1 = 73 cm and a second mass that is 6/7 times as large is placed at x2 = 169 cm. Find the location of the center of mass of the system

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User Kamui
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Answer:

The location of the center of mass of the system is approximately 117.31 cm.

Step-by-step explanation:

To find the center of mass of a system of two objects, you need to consider both their masses and positions. The center of mass (CM) can be calculated using the formula:

CM = (m1 * x1 + m2 * x2) / (m1 + m2)

Where:

CM is the center of mass position

m1 and m2 are the masses of the two objects

x1 and x2 are the positions of the two objects

Given:

m1 = mass of the first object

m2 = 6/7 * m1 (mass of the second object is 6/7 times the mass of the first object)

x1 = 73 cm (position of the first object)

x2 = 169 cm (position of the second object)

Let's plug in the values and calculate:

CM = (m1 * x1 + m2 * x2) / (m1 + m2)

Substitute the value of m2:

m2 = 6/7 * m1

CM = (m1 * x1 + (6/7 * m1) * x2) / (m1 + 6/7 * m1)

Simplify the expression:

CM = (7m1x1 + 6m1x2) / (7m1 + 6m1)

CM = (7x1 + 6x2) / 13

Now, plug in the values of x1 and x2:

x1 = 73 cm

x2 = 169 cm

CM = (7 * 73 + 6 * 169) / 13

CM = (511 + 1014) / 13

CM = 1525 / 13

CM ≈ 117.31 cm

So, the location of the center of mass of the system is approximately 117.31 cm.

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User Miqh
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