Question

Assume it takes 6.65 minutes to fill a 40.0 gal gasoline tank. (1 U.S. gal 231 in.) (a) Calculate the rate at which the tank is filled in gallons per second. galds (b) Calculate the rate at which the tank is filed in cubic meters per second, m/s (c) Determine the time interval, in hours, required to fill a 1.00-m volume at the same rate.

Answer 1

(a) It takes 6.65 minutes, or 399 seconds, to fill a 40.0 gal tank. So, the rate is 40.0 gal / 399 s = 0.100 gal/s.

(b) 1 gal is about 0.00378541 m^3. So, the rate is 0.100 gal/s * 0.00378541 m^3/gal = 0.000378541 m^3/s.

(c) A 1.00 m^3 volume is about 264.172 gal. So, the time to fill this volume is 264.172 gal / 0.100 gal/s = 2641.72 s, or about 0.733 hours.