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A driver added 90 ml of fuel conditioner to 20 L of fuel. How much is needed for 54 L of fuel?

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To find out how much fuel conditioner is needed for 54 L of fuel, we can set up a proportion using the given information.

Let x be the amount of fuel conditioner needed for 54 L of fuel.

According to the given information, the ratio of fuel conditioner to fuel is 90 ml / 20 L.

Therefore, we can set up the proportion:

90 ml / 20 L = x ml / 54 L

To solve for x, we can cross multiply and solve for x:

90 ml * 54 L = 20 L * x ml

4860 ml*L = 20L * x ml

4860 ml*L / 20 L = x ml

243 ml = x

Therefore, 243 ml of fuel conditioner is needed for 54 L of fuel.
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User Ozkan
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