Answer:
128 m/s
Step-by-step explanation:
Take down to be positive.
Given:
Δx = 2750 m
aₓ = 0 m/s²
Δy = 1150 m
v₀ᵧ = 0 m/s
aᵧ = 5.0 m/s²
Find: v₀ₓ
First, find the time it takes for the package to fall:
Δy = v₀ᵧ t + ½ aᵧ t²
1150 = (0) t + ½ (5) t²
1150 = 2.5t²
t = 21.4 s
Now find the initial horizontal velocity of the package:
Δx = v₀ₓ t + ½ aₓ t²
2750 = v₀ₓ (21.4) + ½ (0) (21.4)²
v₀ₓ = 128 m/s