Answer:
Let R1 be the radius of the first circle
And let R2 be the measure of the second circle
So
Arc length = radius * theta ( in rads )
So....since the arc lengths are equal....
R1 * pi/2 = R2 * pi/3
R1 / 2 = R2 / 3
R1 = (2/3)R2
So...the area of the first circle is
[ pi * (R1) ^2 ] = pi *[ (2/3) R2 ] ^2 = pi (4/9) (R2)^2
And the area of the second circle is
pi [ R2]^2
So the ratio of the area of the first circle to the second is
[ pi * (4/9) (R2)^2 ] 4
_______________ = ____
[ pi * (R2)^2 ] 9
= 4/9
Explanation: