Question

What is the midpoint of HJ given H(4, -5) and J(-2, 7)?

Answer 1

midpoint = (1, 1 )

Explanation:

given endpoints (x₁, y₁ ) and (x₂, y₂ ) then midpoint M is

M = (
`(x_(1)+x_(2) )/(2)` ,
`(y_(1)+y_(2) )/(2)` ) ← midpoint formula

let (x₁, y₁ ) = H (4, - 5 ) and (x₂, y₂ ) = J (- 2, 7 )

substitute these values into the formula for M

M = (
`(4-2)/(2)` ,
`(-5+7)/(2)` ) = (
`(2)/(2)` ,
`(2)/(2)` ) = (1, 1 )