Question

Pt = 4x + 9 and tq = 6x - 7 what is the value of pt

Answer 1

• pt = 41

Explanation:

Let, pt = tq

`\hookrightarrow 4x + 9 = 6x - 7`

Subtract 9 from both sides,

`\hookrightarrow 4x + 9 -9 = 6x - 7 - 9`

`\hookrightarrow 4x = 6x - 16`

Subtract 6x from both sides,

`\hookrightarrow 4x - 6x = 6x - 16 - 6x`

`\hookrightarrow -2x = -16`

Divide both sides by -2

`\hookrightarrow x = 8`

Now Plug the value of x in pt.

since pt = 4x + 9

`\hookrightarrow pt = 4(8) + 9`

`\hookrightarrow pt = 32 + 9`

`\hookrightarrow pt = 41`

Henceforth the value of pt is 41

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