Question

What is the boiling point, in °C, of a

1.3 m solution of C6H14 in benzene?
BP (benzene) = 80.10 °C i = 1
Kb (benzene) = 2.65 °C/m
ДТь = (i) (kь)(m)
[?] °C
Hint: Remember significant figures are based
on place value when adding or subtracting.

Answer 1

The boiling point of the 1.3 m solution of C₆H₁₄ in benzene is 83.5 °C.

What is the boiling point, of a 1.3 m solution of C6H14 in benzene?

The boiling point of the 1.3 m (molality) solution of C₆H₁₄ in benzene is determined using the equation:
ΔT = Kb * m



where

ΔT is the boiling point elevation,

Kb is the molal boiling point elevation

constant of the solvent (benzene), and
m is the molality of the solution.

Given data:
Kb (benzene) = 2.65 °C/m

m = 1.3 m

Substituting the values into the equation:
ΔT = 2.65 °C/m * 1.3 m

ΔT = 3.445 °C

Boiling point of the solution = Boiling point of benzene + ΔT

Boiling point of the solution = 80.10 °C + 3.445 °C

Boiling point of the solution = 83.545 °C