asked 49.1k views
5 votes
What is the equation of A line perpendicular to
y = 5x +4 and passes through (1,2)

asked
User Pesama
by
7.9k points

1 Answer

6 votes

Answer:

y = -1/5x +11/5

Explanation:

You want the equation of the line through point (1, 2) and perpendicular to y = 5x +4.

Slope

The slope of the given line is its x-coefficient: 5.

The slope of the perpendicular line is the opposite reciprocal of this: -1/5.

Point-slope equation

The point-slope equation of a line with slope m through point (h, k) is ...

y -k = m(x -h)

Then the equation for the line with slope -1/5 through point (1, 2) is ...

y -2 = -1/5(x -1) . . . . . point-slope equation of the line

Slope-intercept equation

We can rearrange this to slope-intercept form by solving for y and simplifying.

y = -1/5x +1/5 +2

y = -1/5x +11/5 . . . . . slope-intercept equation of the line

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What is the equation of A line perpendicular to y = 5x +4 and passes through (1,2)-example-1
answered
User Simon K
by
8.8k points

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