The elevators in the John Hancock building in Chicago move 826 ft in 30 s. What is their speed? Answer in units of m/s.

Question

asked Feb 6, 2024 129k views

1 Answer

Lelanthran · Answer 1 · 2024-02-12T04:36:16+0000

Answer:

Step-by-step explanation:

Given that: the height of the building is 862 ft

Time taken : 30 seconds

Solve: 1 foot = 0.3048 meters

862 feet = 262.7376 m

now, the speed of elevators = distance/time

= 262.7376/30

= 8.75792

= 8.76 m/s (Approximately)