Question

A bucket of water of mass 25 kg is pulled at constant velocity up to a platform 30 meters above the givund. This takes 10 minutes, during which time 3 kg of water drips out at a steady rate through a hole in the bottom. Find the work needed to ralse the bucket to the platiorm. (Use g=9.8 m/s² ) Work = (include units)

Answer 1

Answer: 81,273 J - 63,213 J = 18,060 J

Step-by-step explanation:

Work done = Force × displacement = (25 kg)(9.81 m/s²)(30 m) - (25 kg)(9.81 m/s²)(3 m) = (25 kg)(9.81 m/s²)(27 m) = 63,213 J

Work done = ΔKE + ΔPE = (0.5)(25 kg)(27 m/s²) + mgh = (0.5)(25 kg)(27 m/s²) + (25 kg)(9.81 m/s²)(3 m) = 81,273 J

So the work needed to raise the bucket to the platform is 81,273 J - 63,213 J = 18,060 J