asked 43.6k views
4 votes
Find the cross product (-3, 1, 2) × (5, 1, 6).
Answer:

asked
User J K
by
7.2k points

1 Answer

1 vote

Answer:

Hi,

Explanation:


\begin{bmatrix}\vec{i}&\vec{j}&\vec{k}\\-3&1&2\\5&1&6\\\end{bmatrix} =\vec{i}*(1*6-1*2)+\vec{j}*(-1)*(-3*6-2*5)+\vec{k}*(-3*1-5*1)\\\\=4*\vec{i}+28*\vec{j}-8\vec{k}\\\\

answered
User Richard Reddy
by
7.9k points

No related questions found