Question

An object with a heat capacity of 345J∘C experiences a temperature change from 88.0∘C to 45.0∘C. How much heat is released in this process, in joules?

Round the answer to three significant figures.
Do not include a negative sign in your response.

Answer 1

To calculate the heat released in this process, we can use the formula:

Q = C * ΔT

Where Q represents the heat released, C represents the heat capacity, and ΔT represents the change in temperature.

Given:

C = 345 J/°C

ΔT = 88.0°C - 45.0°C = 43.0°C

Substituting the values into the formula:

Q = 345 J/°C * 43.0°C

Calculating this expression:

Q = 14,835 J

Therefore, the heat released in this process is 14,835 joules

Step-by-step explanation: