Question

If you dissolve 2.70 g of NaCl in 425 mL of water, what is the molarity of the solution?

Answer 1

Answer: The molarity of the solution is approximately 0.1085 M.

Step-by-step explanation:

First, you need to calculate the moles of NaCl using its molar mass. The molar mass of NaCl (sodium chloride) is approximately 58.44 g/mol (22.99 g/mol for sodium + 35.45 g/mol for chlorine).

Moles of NaCl = Mass / Molar mass

Moles of NaCl = 2.70 g / 58.44 g/mol ≈ 0.04616 moles

Now that you have the moles of NaCl, you can calculate the molarity:

Molarity (M) = Moles / Volume (in liters)

Molarity (M) = 0.04616 moles / 0.425 L ≈ 0.1085 M