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Simplify Name two properties used to evaluate 7 ∙ 1 – 4 ∙ 1/4

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User Tgolisch
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2 Answers

3 votes

Answer:

Two properties are the order of operations and multiplication distributed over subtraction.

Explanation:


\textsf{The two properties used to evaluate $ \sf 7 \cdot 1 -4 \cdot (1)/(4) $ are:}

  • Order of operations:
    This property states that we should perform operations inside parentheses first, followed by exponents, multiplication, division from left to right, and addition and subtraction from left to right.
  • Multiplication distributed over subtraction:
    This property states that we can distribute the multiplication over the subtraction, as follows:

    \sf 7 \cdot 1 - 4 \cdot (1)/(4) = 7 \cdot 1 - (4 \cdot (1)/(4))

Simplifying the expression using the order of operations and the multiplication distributes over subtraction properties, we get:


\sf 7 \cdot 1 - 4 \cdot (1)/(4) = 7 - 1 = 6

Therefore, the simplified expression is 6.

answered
User Mceo
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8.7k points
5 votes

Answer:

1. Identity Property of Multiplication

2. Multiplicative Inverse Property

Explanation:

Given expression:


\large\boxed{7 \cdot 1 - 4 \cdot (1)/(4)}

The two properties that are being used in this expression are:

  1. Identity Property of Multiplication
  2. Multiplicative Inverse Property


\dotfill

Identity Property of Multiplication

This property states that any number multiplied by 1 retains its original value. In other words, the product of any number and 1 is equal to the original number itself.

1 is the multiplicative identity, as it is the unique number that doesn't change the value of other numbers when multiplied by them.

In this case, the product of the number 7 and 1 is equal to the original number, 7.


\dotfill

Multiplicative Inverse Property

This property states that the product of a non-zero number and its reciprocal (multiplicative inverse) is always equal to 1.

In this case, 4 is the number, and 1/4 is the multiplicative inverse (reciprocal) of 4. So their product is 1.


\dotfill

answered
User Jicking
by
8.2k points

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