Question

For the following state of H2O, determine the missing

properties.
P = 220.3 psig,
T = ______ F,
u = ______ kJ/kg,
h = ______ MJ/kg,
rho = 26.69 kg/m3,
s = ______ MJ/kg.K,
x = ______ (state as decimal),

Answer 1

To determine the missing properties of H2O given its pressure, we can use the steam tables to find the corresponding temperature. From there, we can find the specific internal energy, specific enthalpy, specific entropy, and quality of the substance. However, the quality cannot be determined without additional information.

Step-by-step explanation:

To determine the missing properties of H2O, we can use the steam tables. Given the pressure P = 220.3 psig, we can look up the corresponding temperature T in the steam tables. From there, we can use the temperature to find the remaining properties: specific internal energy (u), specific enthalpy (h), specific entropy (s), and quality (x).

1. Using the steam tables, the temperature corresponding to a pressure of 220.3 psig is approximately 420.5°F.
2. Once we know the temperature, we can find the specific internal energy (u). The steam tables provide the specific internal energy values for different temperatures at saturated conditions. Let's assume the state of H2O is saturated:

• For saturated H2O at 420.5°F, the specific internal energy is approximately 1469 kJ/kg.

To find the specific enthalpy (h), we can use the specific internal energy (u) obtained from the steam tables along with the specific volume (rho) and the ideal gas equation:

• The equation is h = u + Pv, where v is the specific volume. We can rearrange the equation to solve for h: h = u + (P/rho).
• Substituting the given values, we have h = 1469 kJ/kg + (220.3 psig / 26.69 kg/m³).
• After converting pressure to kPa and specific volume to m³/kg, we find that the specific enthalpy is approximately 34.89 MJ/kg.

Next, to find the specific entropy (s), we can use the steam tables again. The specific entropy values are provided for different temperatures and pressures. Let's assume the state of H2O is still saturated:

• For saturated H2O at 420.5°F, the specific entropy is approximately 7.321 MJ/kg·K.

Finally, to determine the quality (x) of the H2O, we need to know the phase of the substance. If we know that the substance is purely liquid or purely vapor, then the quality is 0 or 1, respectively. If the substance is a mixture of liquid and vapor, we need additional information to determine the quality. Without this information, we cannot determine the value of x.

Learn more about Properties of H2O