Question

A 70 kg object stands in an elevator. Calculate the normal force acting on the object by the elevator if a) The elevator is moving upward with an acceleration of 3 m/s b) The elevator is moving downward with an acceleration of 3 m/s

Answer 1

upward resultant force=490N

downward=910N

Step-by-step explanation:

upward resultant force=Mg-Ma (70×10 -70×3).

downward resultant force=Mg+Ma

(70×10+70×3)