Question

A new Outdoor Recreation Center is being built in Junction city. The perimeter of the rectangular playing field is 244 yards. The length of the field is 7 yards less then double the width. What are the dimensions of the playing field?

Answer 1

Let's say the width of the field is "x" yards. According to the information given, the length would be "2x - 7" yards. The perimeter of the field is 244 yards, so we can set up an equation:

2(x + 2x - 7) = 244

Simplify the equation and solve for x.

6x - 14 = 244

Adding 14 to both sides of the equation:

6x = 258

Finally, divide both sides of the equation by 6:

x = 43

So the width of the field is 43 yards. To find the length, we can substitute this value back into the expression for the length:

Length = 2x - 7

Length = 2(43) - 7

Length = 86 - 7

Length = 79

Therefore, the dimensions of the playing field are 43 yards by 79 yards.