Question

Express √−9 in terms of the j operator. a. 3 b. −3
c. j3 d. -j3

Answer 1

c

Explanation:

note that j =
`√(-1)`

using the rule of radicals

•
`√(ab)` =
`√(a)` ×
`√(b)`

given

`√(-9)`

=
`√((-1)9)`

=
`√(-1)` ×
`√(9)`

= j × 3

= j3