Answer:
31 inches square
Explanation:
You want to know the original size of a square piece of cardboard that forms an open box with volume 2116 in³ when a 4-in square is removed from each corner and the sides folded up.
Base
The volume of the box is given by ...
V = Bh
where B is the area of the bottom of the box, and h is its height. Solving for B, we have ...
B = V/h = (2116 in³)/(4 in) = 529 in²
Square
Since the base is square, its side length can be found from ...
B = s²
s = √B = √(529 in²) = 23 in
Each side of the box adds 4 inches to the base dimension, so the original square is 8 inches larger in both dimensions.
The original piece of cardboard is a square 31 inches on a side.
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