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Lets lable y=3x-350000 as equation 1 and y=x+590000 as equation 2 by using the substitution method solve for the value of x that satisfies both equations

Lets lable y=3x-350000 as equation 1 and y=x+590000 as equation 2 by using the substitution method solve for the value of x that satisfies both equations
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lets lable y=3x-350000 as equation 1 and y=x+590000 as equation 2 by using the substitution method solve for the value of x that satisfies both equations

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User Iroel
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1 Answer

3 votes

Answer:

the solution that satisfies both equations is x = 470000 and y = 1060000.

Explanation:

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User Nelson Gomes Matias
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