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Solve 6t ^2
−17t−3=0 by factoring. Enter your answers below t= or t=

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3 votes

Answer:


6t^2-17t-3=0\\\text{or,\ }6t^2+(18-1)t-3=0\\\text{or,\ }6t^2+18t-t-3=0\\\text{or,\ }6t(t+3)-1(t+3)=0\\\text{or,\ }(t+3)(6t-1)=0\\\therefore\ t=-3\ \text{or\ }t=(1)/(6)

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User Mateus Viccari
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