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Find the value of r such that \frac{r^2 - 5r + 4}{r^2 - 8r + 7} = \frac{r^2 - 2r - 15}{r^2 - r}

Find the value of r such that \frac{r^2 - 5r + 4}{r^2 - 8r + 7} = \frac{r^2 - 2r - 15}{r^2 - r}
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Find the value of r such that

\frac{r^2 - 5r + 4}{r^2 - 8r + 7} = \frac{r^2 - 2r - 15}{r^2 - r}

asked
User Loman
by
7.5k points

1 Answer

3 votes

Answer:

fracr261587r

Explanation:

\frac = r 2

2r - 15r 2 - r

r = r + r - 7 + 5 r 2

answered
User Renganathan M G
by
7.9k points
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