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Can someone help me find the answer but with the final answer being in radians

Can someone help me find the answer but with the final answer being in radians-example-1

1 Answer

3 votes

Answer:

(1)
-(63)/(65)

(2) 1.318 rad

Explanation:

1.

π ≤ x ≤ 3π/2 → x at Quadran 3 → x-value negative & y-value negative

3π/2 ≤ y ≤ 2π → y at Quadran 4 → x-value positive & y-value negative

∠x :

sin x = -3/5

y : r = -3 : 5

x = √(r² - y²)

= √(5² - (-3)²)

= -4

x : y : r = -4 : -3 : 5

cos x = -4/5

∠y :

sec y = 13/12

cos y = 12/13

x : r = 12 : 13

y = √(r² - x²)

= √(13² - 12²)

= -5

x : y : r = 12 : -5 : 13

sin y = -5/13

cos(x+y) = cos x · cos - sin x · sin y

=
-(4)/(5) *(12)/(13) -(-(3)/(5) )*(-(5)/(13) )

=
-(48)/(65) -(15)/(65)

=
-(63)/(65)

2.

13 - 22cos x - 8sin²x = 0 (assuming incomplete question → the equation = 0)

13 - 22cos x - 8(1 - cos²x) = 0

8cos²x - 22cos x + 5 = 0

(4cos x - 1)(2cos x - 5) = 0

cos x₁ =
(1)/(4)

cos x₂ =
(5)/(2) (not valid, as -1 ≤ cos x ≤ 1)

cos x =
(1)/(4)

x = 1.318 rad

answered
User Will Alexander
by
7.5k points

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