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(4y^4 + 14y^3 + 15y - 6) : (2y^2 -y+2) División larga de polinomios

1 Answer

4 votes

Answer:

2y² + 8y + 2 + (y - 10)/(2y^2 -y+2)

Explanation:

(4y^4 + 14y^3 + 15y - 6) : (2y^2 -y+2) =

2y² + 8y + 2

----------------------------------------

2y² - y + 2 | 4y^4 + 14y³ + 0y² + 15y - 6

(-) 4y^4 - 2y³ + 4y²

16y³ - 4y² + 15y

(-) 16y³ - 8y² + 16y

4y² - y - 6

(-) 4y² - 2y + 4

y - 10

(4y^4 + 14y^3 + 15y - 6) : (2y^2 -y+2) = 2y² + 8y + 2 + (y - 10)/(2y^2 -y+2)

answered
User Latik
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