Question

Determine the surface area of a box whose length l is 21 feet,

width w is 7feet, and height h is 10.1 feet?

Answer 1

Explanation:

Since all the alternate edges are different in length, the box is a cuboid. Surface area of cuboid is calculated by:

`\boxed{ \rm{Surface \: area =}2(lb + bh + lh)}`

Given measure of length = 21 ft, width is 7 ft and height is 10.1 ft. Surface area of the box is:

= 2(21*7 + 10.1*7 + 21*10.1) ft²

= 859.6 ft²

Surface area of the block is 859.6 ft²